4a^2-26a+12=0

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Solution for 4a^2-26a+12=0 equation:



4a^2-26a+12=0
a = 4; b = -26; c = +12;
Δ = b2-4ac
Δ = -262-4·4·12
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-26)-22}{2*4}=\frac{4}{8} =1/2 $
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-26)+22}{2*4}=\frac{48}{8} =6 $

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